Question

You push a 35.5‑kg wooden box
across a wooden floor at a constant speed of 1.5 m/s. The coefficient of
kinetic friction is 0.15. How large is the force that you exert on the box?

Answer 1

Answer:

532.5 Newton.

Explanation:

Friction = 0.15× mg

= 0.15× 35.5 × 10

= 532.5 N

Force = Friction { because body is moving with constant speed}

Force = 532.5 Newton.

Answer 2

Answer:

You exert a force of 52.2 N on the box to push it at a constant speed of 1.5 m/s across the wooden floor.

Explanation:

The force that you exert on the box is equal in magnitude and opposite in direction to the force of friction acting on the box.

The force of friction can be calculated using the formula:

f = μk * N

where f is the force of friction, μk is the coefficient of kinetic friction, and N is the normal force acting on the box (the force perpendicular to the surface of the floor).

The normal force is equal in magnitude to the weight of the box, which is:

N = m * g

where m is the mass of the box and g is the acceleration due to gravity (9.8 m/s^2).

Substituting the given values, we get:

N = m * g = 35.5 kg * 9.8 m/s^2 = 347.9 N

f = μk * N = 0.15 * 347.9 N = 52.2 N

Since the box is moving at a constant speed, the net force on the box is zero. Therefore, the force that you exert on the box must be equal in magnitude to the force of friction:

F = f = 52.2 N

Therefore, you exert a force of 52.2 N on the box to push it at a constant speed of 1.5 m/s across the wooden floor.

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