You raise very important nitrogenous fertilizers it formula is seo and 284 calculate the percentage of nitrogen in urea
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urea=> NH2-CO-NH2
total mass=60
mass of nitrogen = 14, 2 molecules hence m=28
N%= mass of nitrogen X 100
mass of urea
= 28 X 100
60
N%= 46.6%
total mass=60
mass of nitrogen = 14, 2 molecules hence m=28
N%= mass of nitrogen X 100
mass of urea
= 28 X 100
60
N%= 46.6%
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