Question

You randomly draw a marble from a bag of marbles that contains 777 blue marbles, 222 green marbles, and 111 red marble.
What is{P(not draw a blue marble})P
If necessary, round your answer to
2 decimal places.

Answer 1

Answer:

3/10 answer

Step-by-step explanation:

Answer 2

Answer:

Concept:

Probability:

The likelihood that an event will occur is expressed by probability. The probability of an event is defined as P by the ratio of the number of favorable outcomes of an event A to all other possible outcomes (A).

          $P(A)=\frac{n(A)}{n(S)}$

Where,

P(A) = Probability or likelihood of event A.

n(A) = the number of favorable results for A.

n(S) = The overall number of outcomes.

Given:

Number of Blue Marbles $=777$

Number of Green Marbles $=222$

Number of Red Marbles $=111$

To Find:

We need to find the probability of not getting blue ball.

Solution:

Possible outcomes or total number of marbles n(S) is the sum of number of Blue Marbles, number of Green Marbles and number of Red Marbles.

$n(S) = 777+222+111=1110$

Let $n(A)$  be the number of balls which is not blue. So subtract the number of blue marbles from the total number of marbles.

⇒  $n(A) = n(S) - 777$

⇒  $n(A) = 1110 - 777$

⇒  $n(A)=333$

Then,

⇒  $P(A)=\frac{n(A)}{n(S)}$

⇒  $P(A)=\frac{333}{1110}$

⇒  $P(A)=\frac{3}{10}$

⇒  $P(A)=0.3$

P(Not Getting Blue Marble) is $0.30$.

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