Question

You're riding a toboggan down an icy run to a frozen lake, and you accelerate the
80.0-kg combination of you and the toboggan from 1.0 m/s to 2.0 m/s in 2.0 s. How
much power does that require?​

Answer 1

Answer:

40 joule/sec

Explanation:

Power = work / time.

Now,

We have, F = m a

Power = work / time.Now, We have, F = m a =

$\frac{m(v - u)}{t} \\ \\ = > \frac{80(2 - 1)}{2} = 40 \: newton$

now,

$s = ut + \frac{1}{2} a {t}^{2} \\ = > 2 + \frac{1}{2} \times ( \frac{v - u)}{t} \times {t}^{2} \\ = > 1 + \frac{1}{2} \times 1 \times 2 \\ = > 2$

Hence, Work = force × displacement = 40 × 2 = 80 J.

Hence, power = work /time =

$\frac{80}{ 2} = 40 \: j {s}^{ - 1}$

Regards

Kshitij