Question

you resolve this contradictoll!
4. Represent √9.3 on the number line.​

Answer 1

Answer:

just draw line of 9.3 cm and mark it as a and b and then extend it 1 cm mark it as b and c then draw perpendicular of whole line which is 10.3cm and then take radius for drawing semicircle which will be equal to half of the line then draw semi circle ,mark the centre as E then extend the line to some distance as a dotted line and from b draw a line which will touch semicircle mark the point which touch the circle as D then take ED as radius then make a arc on which will cut on extended line and point where where arc cuts line is ur√9.3

Answer 2

Step-by-step explanation:

STEPS: 1: On a numberline mark AB = 9.3 unit & BC= 1 unit. ( & why 1 unit, I've given the reason in comment section)

2: Mark O the mid point of AC

3: Draw a semicircle with O as centre & OA as radius

4: At B draw a perpendicular BD.

5: BD = √9.3 unit

6: Now, B as centre, BD as radius, draw an arc, meeting the numberline at E.

Now, with BD or BE = √9.3 as radius , with 0 ( origin) of the number line as centre, draw an arc on the the number line, intersecting at point ‘k’. And this point ‘k' lies between integers 3 & 4, & represents √9.3