Question

You roll a biased coin (p(head)=0.8 five times. what's the probability of getting four or more heads?​

Answer 1

Explanation:

First of all, you’re flipping a coin, not rolling it.

To start off the question, we need 3, 4, or 5 heads to satisfy the cases.

5 heads: All heads, so (4/5)^5=1024/3125

4 heads: All heads but 1. There are 5 ways to organize this, and then a (4/5)^4*(1/5)^1=256/3125. Since there are 5 cases, we have 1280/3125.

3 heads: All heads but 2. There are 10 ways to organize this, and then a (4/5)^3*(1/5)^2=64/3125. Since there are 10 cases, we have 640/3125.

We sum all these cases up to get (1024+1280+640)/3125=2944/3125.

We have a 2944/3125 or 0.94208 probability to get 3 or more heads.

Answer 2

Answer:

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Explanation:

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