Question

You roll a number cube numbered from 1 to 6. What is the probability that the number is a composite number?
(Answers are rounded to the nearest hundredth percent.)

16.66%

67.33%

33.33%

11.11%

20.00%

Answer 1

Answer:

There are 33.33% chance of getting a composite number.

Step-by-step explanation:

Total number of outcomes = 6

Composite number between 1 to 6 are 4 and 6.

So, Total number of favourable outcomes = 2

Probability of getting a composite number:

= F/T = 2/6 = 1/3

Convert it in percentage:

1/3 × 100%

= 33.33 %

Answer 2

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

● You roll a number cube numbered from 1 to 6. ⠀⠀

$\sf{\bold{\red{\underline{\underline{To\:Find}}}}}$

☆ probability of the composite number in percentage???

$\sf{\bold{\purple{\underline{\underline{solution}}}}}$

Here,

Total number of outcomes =$\tt{|T|=6 }$ ⠀

But here,

6 and 4 are the composite number between 1 to 6.

Then,

Favourable outcomes =$\tt{|F|=2 }$ ⠀

we know that,

$\boxed{\underline{\underbrace{\mathcal\color{gold}{probability=\dfrac{Total~number ~of ~observation}{Total ~number ~of ~products}}}}}$

so,

Probability of a composite number $\implies$ ⠀

:$\rightsquigarrow$ $\tt{\dfrac{F}{T} }$ ⠀

:$\rightsquigarrow$ $\tt{\dfrac{2}{6} }$ ⠀

:$\rightsquigarrow$ $\tt{\dfrac{\cancel{2}}{\cancel{6}} }$ ⠀

:$\rightsquigarrow$ $\tt{\dfrac{1}{3} }$ ⠀

Now,

$\rightsquigarrow$ $\huge{\underline{ percentage:- }}$ ⠀

:$\rightsquigarrow$ $\tt{\dfrac{1}{3}×100\% }$ ⠀

:$\rightsquigarrow$ $\tt{33.33\% }$ ⠀