Question

You roll two number cubes. What is the probability of rolling double threes?

Answer 1

Given :- You roll two number cubes in the form of dice. What is the probability of rolling double threes ?

Solution :-

we know that, when two dice in the form of cubes are tossed once, then possible events will be

• (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
• (2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
• (3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
• (4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
• (5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
• (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
• Total = 36 .

so,

→ Total favourable outcomes = (3,3) = 1

→ Total number of outcomes = 36 .

therefore,

→ Required probability = Total favourable outcomes / Total number of outcomes = (1/36) (Ans.)

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Answer 2

Given:

You roll two number cubes. What is the probability of rolling double threes?

Solution

When two dice are thrown, then the possible events will be:

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

In the above possible events, the favorable outcome: double threes (3,3) is only 1.

The total number of outcomes is 36.

=> probability of rolling double threes:

=> favorable outcomes / total number of outcomes

=> 1 / 36

Hence, the required answer is 1/36