English, asked by aafzalmohammedkhan, 1 month ago

You sita/suresh are being to a crowed area in byculla. write to your friend Arpita/Aruesh who lives in a clean area tell about the dirt garbage throw around in your place​

Answers

Answered by ejazbano7
3

Answer:

123- Metro Apt.

Jahagirpuri

Delhi-110033

Date - 4-5-2020

Dear Mridual

I hope you are in pink of your health. I am writing this letter to inform you that the garbage is dumped in open places in your whole town is causing health hazards to people. In a survey conducted by Times of India, it came into light that so many people are suffering from respiratory problems due to this. The data are shocking. It is mainly with the people residing near those hills of garbage i.e. Noida and Rohini.

We have wriiten a letter to the chief minister of Delhi regarding this.

Do share if you are also facing any such problem in your city.

Give my regards to uncle and aunty.

Your loving friend

Amit

Answered by surendragadhveer
1

Explanation:

Solution

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Let the tailor P work for x days and the tailor Q work for y days respectively.

Z=150x+200y

Here the problem can be formulated as an L.P.P. as follows

Minimize Z=150x+200y

Subject to the constraints

6x+10y≥60

⇒3x+5y≥30

4x+4y≥32

x+y≥8

and x≥0,y≥0

Converting them into equations we obtain the following equations

3x+5y=30,

⇒y=

5

30−3x

x 0 10 5

y 6 0 3

⇒x+y=8

y=8−x

x 0 8 5

y 8 0 3

The lines are shown on the graph paper and the feasible region (Unbounded convex) is shown shaded.

The corner points are

A(10,0),B(5,3) and C(0,8)

At the corner point the value of Z=150x+200y

At A(10,0)Z=1500

At B(5, 3), Z=150×5+200×3=750+600=1350

At C (0, 8), Z=1600

As the feasible region is unbounded, we draw the graph of the half-plane

150x+200y<1350

3x+4y<27

There is no point common with the feasible region, therefore, Z has minimum value.

Minimum value of Z is Rs. 1350 and it occurs at the point B(5,3).

Hence, the labour cost is Rs. 1350 when P works for 5 days and Q works for 3 days.

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