Question

you start jogging around a park with a velocity of 80 m/s.you get tired and deaccelerate at the rate of 2m/s.in how many se onds will you come to rest​

Answer 1

Answer:

40 seconds

Explanation:

As per the provided information in the given question, we have :

• Initial velocity (u) = 80 m/s
• Final velocity (v) = 0 (As I come to rest)
• Acceleration (a) = – 2m/s²

We are asked to calculate that in how many seconds shall I come to rest.

By using the first equation of motion,

⇒ v = u + at

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

⇒ 0 = 80 + (–2t)

⇒ 0 – 80 = –2t

⇒ –80 = – 2t

⇒ –80 ÷ (–2) = t

⇒ 40 seconds = t

Therefore, in 40 seconds I'll come to rest.

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More Information :

Equations of motion :

$\boxed{ \begin{array}{cc} \pmb{\sf{ \quad \: v = u + at \quad}} \\ \\ \pmb{\sf{ \quad \: s= ut + \cfrac{1}{2}a{t}^{2} \quad \: } } \\ \\ \pmb{\sf{ \quad \: {v}^{2} - {u}^{2} = 2as \quad \:}}\end{array}}$

• v denotes final velocity
• u denotes initial velocity
• t denotes time
• s denotes distance
• a denotes acceleration