Question

You throw a ball up and its height h can be tracked using the equation: h = 2x^2 − 12x 20. What is the highest the ball will reach? B) When will the ball land (i.e. hit 0 feet high)?

Answer 1

3 + i  will be time when ball will land on the ground.

Step-by-step explanation:

Correct equation:

h = 2x²  - 12x  + 20

dh/dt = 4x - 12

• Velocity will be zero at highest point

4x - 12 = 0

x = 12/4

x = 3

• After 3 Secs Ball will reach highest point

Height at 3 seconds

=  2(3)²  - 12(3) + 20

= 18 - 36 + 20

= 38 - 36

= 2

• At 3 Sec , Ball will reach highest  2 feet

When ball will land height becomes zero.

Height "h" = 0

2x²  - 12x  + 20 = 0

x² - 6x + 10 = 0

x = (6 ± √-4)/2

= ( 6 ± 2i)/2

= 3 ± i

Thus 3 + i  will be time when ball will land.

Also learn more

A ball is dropped vertically from a height of 12 m from rest. After striking the ground, it bounces to a height of 9 m. What fraction of Kinetic Energy it lose on striking the ground?

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