You throw a ball up and its height h can be tracked using the equation: h = 2x^2 − 12x 20. What is the highest the ball will reach? B) When will the ball land (i.e. hit 0 feet high)?
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3 + i will be time when ball will land on the ground.
Step-by-step explanation:
Correct equation:
h = 2x² - 12x + 20
dh/dt = 4x - 12
- Velocity will be zero at highest point
4x - 12 = 0
x = 12/4
x = 3
- After 3 Secs Ball will reach highest point
Height at 3 seconds
= 2(3)² - 12(3) + 20
= 18 - 36 + 20
= 38 - 36
= 2
- At 3 Sec , Ball will reach highest 2 feet
When ball will land height becomes zero.
Height "h" = 0
2x² - 12x + 20 = 0
x² - 6x + 10 = 0
x = (6 ± √-4)/2
= ( 6 ± 2i)/2
= 3 ± i
Thus 3 + i will be time when ball will land.
Also learn more
A ball is dropped vertically from a height of 12 m from rest. After striking the ground, it bounces to a height of 9 m. What fraction of Kinetic Energy it lose on striking the ground?
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