You walk? 3ˆi + 7ˆj ? m and then ? 12ˆi − 4ˆj ? m. From the same starting point, your friend walks? −4ˆi + 11ˆj ? m and stops. If from your current position you were to run uniformly towards your friend in 5 seconds, what would be your velocity?
Answers
your current position = 15i + 3j
your friends position = -4i + 11j
distance between you and your friend = 19i + 8j
time taken = 5s
speed = 19/5i + 8/5j = 3.8i + 1.6j OR 4.1 m/s
Given : You walk 3ˆi + 7ˆj m and then 12ˆi − 4ˆj m
From the same starting point, your friend walks −4ˆi + 11ˆj m
From your current position you were to run uniformly towards your friend in 5 seconds
To Find : velocity
Solution:
Your position 3ˆi + 7ˆj + 12ˆi − 4ˆj = 15ˆi + 3ˆj m
Friend position = −4ˆi + 11ˆj m
Displacement = −4ˆi + 11ˆj - ( 15ˆi + 3ˆj)
(-19 i + 8 j) m
time = 5 secs
Velocity = -3.8 i + 1.6 j m/s
Velocity = (√(-19)² + (8)² )/ 5
= 4.123 m/s
Velocity is 4.123 m/s
-3.8 i + 1.6 j m/s
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