Question

You want to operate an air conditionar of rating 2kw at 220v in a electric circuit in which 5bulb of 60w at 220v rating is arr already operating what should be the minimum current rating of the fuse safty point of view justify

Answer 1

Power P = VI = 2000 W            V = 220 VCurrent drawn I = P/V = 2000 W/220 V = 9.09 A The current drawn by the air conditioner is 9 A , which is much greater than the capacity of the fuse in the circuit, i.e., 5 A. So when a high current of 9 A flows through the 5 A fuse, the fuse wire will get heated to such an extent that it melts and breaks the circuit, cutting off the power supply. Hence when an air conditioner of rating 2000 W; 220 V is operated in a domestic circuit that has a current rating of 5 A, the fuse will blow off cutting off the power supply in the circuit.

Answer 2

for air conditioner the required current will be given by formula P=VI
We know p= 2000 w and v is 220V
so current I is P/V= 2000/220=9.09 A
Now for one bulb same formula is used
I=P/V
60/220= 0.27A
now for five bulbs current needed is 0.27×5 which is 1.35 A
now add 1.35 with 9.09= 10.44 A
so we will use fuse of rating 11A
REASON: the normal current required is 10.44 A so we take a slightly higher rated fuse( slightly higher than 10.44) so if current is in normal limit it will not melt but once current flows more than safe limit it will melt to prevent damage to electrical equipment.
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