You want to send postcards to 12 friends. In the shop there are only 3 kinds of postcards. In how many ways can you send the postcards, if
(a) there is a large number of each kind of postcard, and you want to send one card to each friend;
(b) there is a large number of each kind of postcard, and you are willing to send one or more postcards to each friend (but no one should get two identical cards);
(c) the shop has only 4 of each kind of postcard, and you want to send one card to each friend?
Answers
Answer:
(a) ways
(b) * 12! ways
(c) ways
Step-by-step explanation:
From the above question,
They have given :
1. There are 3 types of postcards.
2. Each type can be sent to 12 friends in 12 different combinations.
3. Therefore, the total number of combinations is 3 x 12 = 36.
In this case, you can send the postcards in 36 different ways. This is because there are 3 types of postcards, and each type can be sent to 12 friends in 12 different combinations. Therefore, the total number of combinations is 3 x 12 = 36.
Answer:
(a) ways
There are 3 options for the first friend, 3 options for the second friend and so on. This can be expressed as 3x3x3x3x3x3x3x3x3x3x3x3
(b) * 12! ways
Since you want to make sure that no one gets two identical cards, you need to first choose which card each person will get (3^12) and then arrange the cards in a unique way (12!).
(c) ways
Since there are only 4 of each kind of postcard, you have 4 options for the first friend, 4 options for the second friend and so on. This can be expressed as 4x4x4x4x4x4x4x4x4x4x4x4
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Answer:
(a) ways
(b) * 12! ways
(c) ways
Step-by-step explanation:
From the above question,
They gave:
1. There are 3 types of postcards.
2. Each type can be sent to 12 friends in 12 different combinations.
3. So the total number of combinations is 3 x 12 = 36.
In this case, you can send postcards in 36 different ways. There are 3 types of postcards and each type can be sent to 12 friends in 12 different combinations. So the total number of combinations is 3 x 12 = 36.
Reply:
(a) ways
There are 3 choices for the first friend, 3 choices for the second friend, and so on. This can be expressed as 3x3x3x3x3x3x3x3x3x3x3x3
(b) * 12! ways
Since you want to make sure no one gets two of the same card, you first have to choose which card each gets (3^12) and then arrange the cards in a unique way (12!).
(c) ways
Since there are only 4 cards of each type, you have 4 choices for the first friend, 4 choices for the second friend, and so on. This can be expressed as 4x4x4x4x4x4x4x4x4x4x4x4
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