Question

you will give me right answer I will make your brain list​

Answer 1

Answer:

R={(x,y):y=x+5andx<4}={(1,6),(2,7),(3,8)}

It is seen that (1,1)∈/

R⇒R is not reflexive.

Also (1,6)∈R.

But, (1,6)∈/

R. ∴R is not symmetric.

Now, since there is no pair in R such that (x,y) and (y,z)∈R, then (x,z) cannot belong to R.

∴ R is reflexive.

As x and x work at the same place, given relation is reflexive.

Answer 2

Answer:

R=[(x,y):y=x+5andx<4}-{(1,6),(2,7),(3,8)}

It is seen that (1,1) €/

R→ R is not reflexive.

Also (1,6)ER.

But, (1,6)€/

R. R is not symmetric.

Now, since there is no pair in R such that (x,y) and (y,z)ER, then (x,z) cannot belong to R.

.. R is reflexive.

As x and x work at the same place, given relation is reflexive.