Question

Young’s double slit experiment, the slit separation is reduced to half and distance of the screen is increased by 50 %. If X is the initial fringe width then new fringe width is *​

Answer 1

Answer:

quadrupled

Explanation:

Fringe width β=λD/d

Fringe with on making separation d/2,

distance between screen and slit 2D = λ∗2D/(d/2)=4λD/d

So fringe with is quadrupled.

Answer 2

Since in YDSE, angular width is given by
Angular Width A.W.=
D
β
​
=
d
λ
​


For a given wavelength,
A.W.
1
​
d
1
​
=A.W.
2
​
d
2
​

0.20×2=0.21×d
2
​

d
2
​
=