Young's modulus elasticity of steel is 19×10 raise to power 10 Newton/m2 into dyne/m2
1 NEWTON=100000 DYNE
its urgent......
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Answered by
7
unit of Young's modulus is N/m^2
Therefore, its dimensions = (Force)/(Distance)^2
[Y] = [MLT^-2]/[L^2] = [ML^-1T^-2]
1N/m^2 = (1kg) (1m^-1) (1s^-2)
1 dyne/cm^2 =(1g) (1cm^-1) (1s^-2)
Therefore, 1N/m^2/1dyne/cm^2 = (1kg/1g) (1m/1cm)^-1 (1s/1s)^-2
= (10^3g/1g) (10^2cm/1cm)^-1 (1)^-2
= 1000 * 1/100 * 1
=10
So, 1N/m^2 = 10 dyne/cm^2
Hence,19*10^10 Newton/m^2 = (19*10^10)*10 dyne/cm^2 = 19 x 10^11 dyne/cm^2
Therefore, its dimensions = (Force)/(Distance)^2
[Y] = [MLT^-2]/[L^2] = [ML^-1T^-2]
1N/m^2 = (1kg) (1m^-1) (1s^-2)
1 dyne/cm^2 =(1g) (1cm^-1) (1s^-2)
Therefore, 1N/m^2/1dyne/cm^2 = (1kg/1g) (1m/1cm)^-1 (1s/1s)^-2
= (10^3g/1g) (10^2cm/1cm)^-1 (1)^-2
= 1000 * 1/100 * 1
=10
So, 1N/m^2 = 10 dyne/cm^2
Hence,19*10^10 Newton/m^2 = (19*10^10)*10 dyne/cm^2 = 19 x 10^11 dyne/cm^2
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Answered by
3
Y = 19 * 10¹° Newton / m²
1 Newton = 1 kg-m/sec² = 1000 gm- 100cm/sec²
= 10⁵ gm-cm/sec² = 10⁵ dyne
m² = 100² cm²
Newton/m² = 10⁵ dyne/m² = 10⁵ dyne/10⁴ cm² = 10 dyne/cm²
Y = 19 * 10¹° Newton/m²
= 19 * 10¹° * 10⁵ dyne/m²
= 19 * 10¹⁵ dyne/m²
= 19 * 10¹¹ dyne/cm²
1 Newton = 1 kg-m/sec² = 1000 gm- 100cm/sec²
= 10⁵ gm-cm/sec² = 10⁵ dyne
m² = 100² cm²
Newton/m² = 10⁵ dyne/m² = 10⁵ dyne/10⁴ cm² = 10 dyne/cm²
Y = 19 * 10¹° Newton/m²
= 19 * 10¹° * 10⁵ dyne/m²
= 19 * 10¹⁵ dyne/m²
= 19 * 10¹¹ dyne/cm²
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