Question

Young's modulus of a metal is 15xx10^(11) Pa. If its Poisson's ratio is 0.4. The bulk modulus of the metal in Pa is

Answer 1

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Young's modulus Y=15×1011 (given)

Poisson's ratio σ=0.4

Using 3kY=1−2σ (standard result)

where k is Bulk's modulus

Thus we get Y=3k(1−2σ)

∴ 15×1011=3(1−0.8)k

⟹ k=25×1011 Pa

Answer 2

Answer:

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Explanation:

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