Physics, asked by priyabratapanda9696, 12 hours ago

Young's modulus of a metal is 9.8x10¹¹dyne/cm². What does it mean ? ​

Answers

Answered by s02371joshuaprince47
14

Answer:

The unit Young's modulus is `N/m^2

Young's modulus of a metal is 9.8x10¹¹dyne/cm² and  its breaking stress is 11000 kg/cm2

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Answered by yassersayeed
3

Given: Young's modulus of a metal = 9.8 \times 10^{11} \text { dyne/cm }^{2}

As we know that,

=>1 \mathrm{~N}=10^{5} \text { dyne }\\\\=>1 \mathrm{~m}=100 \mathrm{~cm}\\\\\text { Thus, } 9.8 \times 10^{10} \mathrm{~N} / \mathrm{m}^{2}=9.8 \times 10^{10} \times 10^{5} /(100)^{2}=19 \times 10^{11}

Now,

=>9.8 \times 10^{11} dyne/cm^{2} =9.8 \times 10^{10} \mathrm{Nm}^{-2}

So, we can conclude that Young's modulus of metal is =>9.8 \times 10^{11} dyne/cm^{2} =9.8 \times 10^{10} \mathrm{Nm}^{-2}

Hence, Young's modulus of metal will be 9.8 \times 10^{10} \mathrm{Nm}^{-2}

                       

       

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