Physics, asked by sasarita9453, 10 months ago

Young's modulus of elasticity of brass is 10 power 11 the increase in its energy and pressing a rod of length 2.1 m and cross sectional area 1 cm square made of brass with a force of 10 kg along its length will be

Answers

Answered by chlorineradicle
13

(100*2.1)/(0.0001*10^11)= strain= 2.1*10^-5 m

energy = 1/2 * stress* strain

= 1/2*. 100* 2.1*10^-5.

= 1.05* 10^ -3 joules

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