Question

Your brother drops a ball from 1 meter above the ground. On every successive bounce, the ball bounces back into the air one half of the distance from its previous
Deak So, the ball initially bounces 12 meter, then falls back down, then bounced V4 meter, etc. This continues forever. What is the total distance the ball travels?
o 3 meters
o 2 meters
0 2.5 meters
4 meters​

Answer 1

Answer:

Short answer:

1+(1/2+1/2)+(1/4+1/4)=1+1+1/2=2½

Explanation:

After 1st drop h=1m

Then, bounces up 1/2 m and comes down so total1(1/2+1/2=1m)

Then, again it bounces up 1/4 and comes down, total2(1/4+1/4=1/2m)

So, total distance after 3rd drop=2½m

Answer 2

Answer:

Answer:

Short answer:

1+(1/2+1/2)+(1/4+1/4)=1+1+1/2=2½

Explanation:

After 1st drop h=1m

Then, bounces up 1/2 m and comes down so total1(1/2+1/2=1m)

Then, again it bounces up 1/4 and comes down, total2(1/4+1/4=1/2m)

So, total distance after 3rd drop=2½m

Step-by-step explanation:

Hope this answer will help you.