Your search - Find all the zeros of the polynomial p(x)=x³+13x²+32x+20 if one of its zeros is -2 .
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Since, (- 2) is a zero of the given polynomial, then (x + 2) is a factor of it.
Now, p (x) = x^3 + 13x^2 + 32x + 20
= x^3 + 2x^2 + 11x^2 + 22x + 10x + 20
= x^2 (x + 2) + 11x (x + 2) + 10 (x + 2)
= (x + 2) (x^2 + 11x + 10)
= (x + 2) (x^2 + x + 10x + 10)
= (x + 2) {x (x + 1) + 10 (x + 1)}
= (x + 2) (x + 1) (x + 10)
Therefore, the other zeroes are (- 1) and (- 10).
Hope it helps!
Since, (- 2) is a zero of the given polynomial, then (x + 2) is a factor of it.
Now, p (x) = x^3 + 13x^2 + 32x + 20
= x^3 + 2x^2 + 11x^2 + 22x + 10x + 20
= x^2 (x + 2) + 11x (x + 2) + 10 (x + 2)
= (x + 2) (x^2 + 11x + 10)
= (x + 2) (x^2 + x + 10x + 10)
= (x + 2) {x (x + 1) + 10 (x + 1)}
= (x + 2) (x + 1) (x + 10)
Therefore, the other zeroes are (- 1) and (- 10).
Hope it helps!
Falguny:
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