Question

youv
Date:
how much heat energy
is necessary to
raise the temperature of 150 kg of water from 30° celsius to 100° celsius
​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Given:

mass(m)=1kg

Heat energy required (Q)=?

Rise in temperature Δt=100−20=80

∘

C=80K

Specific heat capacity (c) 483Jkg

−1

K

−1

Specific heat capacity (c) =

Mass(m)×Riseintemperature

Heatenergy(Q)

483=Q/(1×80)

Q=38640J

Step-by-step explanation:

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