Question

yrr please answer dedo

⟹worng answer : 5 answers report
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Answer 1

Answer:

a) 85 degree

Step-by-step explanation:

hope it is help ful

Answer 2

First Answer

$\pink{S}\purple{O}\green{L}\blue{O}\orange{T}\red{I}\pink{O}\purple{N} =$

Given figure, if AB || CD || EF, PQ || RS, RQD=25° and CQP=60°,

Then ∠SRB=∠CQP=60°

Then ∠SRB=∠CQP=60°OR ∠QRA=∠RQD=25°

Then ∠SRB=∠CQP=60°OR ∠QRA=∠RQD=25°

Then ∠SRB=∠CQP=60°OR ∠QRA=∠RQD=25° So ∠ARS+∠SRB=180°

Then ∠SRB=∠CQP=60°OR ∠QRA=∠RQD=25° So ∠ARS+∠SRB=180°

Then ∠SRB=∠CQP=60°OR ∠QRA=∠RQD=25° So ∠ARS+∠SRB=180° ∴∠ARS=120−60=120°

∠QRS=∠ARS+∠QRA=120+25=145°

Option C )145°

Second Answer

$\pink{S}\purple{O}\green{L}\blue{O}\orange{T}\red{I}\pink{O}\purple{N} =$

Let the angles of a triabgle be α,β,γ

Let the angles of a triabgle be α,β,γGiven α+β=γ

We now that in a sum of triangles sum of angles is is 180°

So,α+β+γ=180°

⟹2γ=180°

⟹γ=90°

So, it is a right angled triangle.

Option D) Right angle triangle