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ii) The angles of a quadrilateral are in the ratio 1: 2:3: 4. Find all its angles.
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Answered by
1
Let 1st angle = 1x
2nd angle = 2x
3rd angle = 3x
4th angle = 4x
We know that,
Sum of all angles of a quadrilateral = 360°
1x + 2x + 3x + 4x = 360°
10x = 360°
x = 360/10
x = 36°
so
1st angle = 1x = 1×36 = 36°
2nd angle = 2x = 2×36 = 72°
3rd angle = 3x = 3×36 = 108°
4th angle = 4x = 4×36 = 144°
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Answered by
41
- Let the common angle be = x
We know that sum of angles of a quadrilateral is 360° .
So , According to the given situation ,
- 1x + 2x + 3x + 4x = 360°
- 10x = 360°
- x = 360/10 = 36°
So , putting x in all we get ,
1x = 1 × 36 = 36°
2x = 2 × 36 = 72°
3x = 3 × 36 = 108°
4x = 4 × 36 = 144°
So , all the angles of a quadrilateral are , 36° , 72° , 108° and 144°.
36 + 72 + 108 + 144 = 360°
360° = 360°
Hence , the angles are 36 , 72,
108 and 144
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