Question

ywo numbers x and y are such that x>y if the difference of these numbers is 5and product is 24 find the sum of two numbers,difference of their cubes and sum of the two cubes

Answer 1

Given, x-y= 5
           xy=24
⇒xy=24 ∴x=24/y
(Substitute in x-y=5)

⇒24/y-y=5 (LCM =y)
⇒24 -y²=5y
⇒y²+5y-24=0

⇒y²-3y+8y-24=0
∴ We get(y-3) (y+8)
∴y=3 and x=8

x+y= 8+3=11

x³- y³= (8)³ - (3)³ = 648 -27=621
x³ + y³= 648 +27=675

Answer 2

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