yz-(zx-xy-yz-(zx+yz)-(2xy-zx)
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Answer:
xy−[yz−zx−yx−(3y−xz)−(x−y−2y)]
=xy−[yz−zx−yx−3y+xz−x+y+2y]
=xy−[yz−yx−x]
=xy−yx+xy+x
=2xy−yx+x
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