Question

z=1+i/1-i then z^8 equals to

Answer 1

Hello mate!.....
$given..... \\ z = \frac{1 + i}{1 - i} \\ z {}^{8} = \frac{(1 + i) {}^{8} }{(1 - i) {}^{8} } \\ z {}^{8} = \frac{((1 + i) {}^{2}) {}^{4} }{(1 + 1 - 2i) {}^{4} } \\ z {}^{8} = \frac{(2i) {}^{4} }{16} \\ z {}^{8} = \frac{16}{16 } \\ z {}^{8} = 1$
HOPE IT HELPS U DEAR....