Question

(z−1)(z−1) can be written
step by step solutions please​​

Answer 1

Answer:

$(z - 1)(z - 1) = {(z - 1)}^{2}$

$identity$

${(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}$

${(z - 1)}^{2} = {z}^{2} - 2 \times z \times 1 + {1}^{2}$

$= {z}^{2} - 2z + 1$

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Answer 2

Answer:

(z−1)(z−1)=(z−1)

2

identityidentity

{(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}(x−y)

2

=x 2 −2xy+y 2

{(z - 1)}^{2} = {z}^{2} - 2 \times z \times 1 + {1}^{2}(z−1)

2

=z 2−2×z×1+1 2

= {z}^{2} - 2z + 1

=z 2−2z+1

Step-by-step explanation:

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