Question

z+1,z-1,y+17,y-17 solve it​

Answer 1

Answer:

Step-by-step explanation:

{(z + 1)(z - 1)} {(y+ 17)(y - 17)}

(z^2 - 1^2)( y^2 - 17^2)

(z^2 - 1)(y^2 - 289)

Answer 2

The product of z + 1, z - 1, y + 17, y - 17 = $(z^2 - 1)(y^2 - 289)$

Step-by-step explanation:

We have,

z + 1, z - 1, y + 17, y - 17

To find, the product of z + 1, z - 1, y + 17, y - 17 = ?

∴ z + 1, z - 1, y + 17, y - 17

= ${(z + 1)(z - 1)}{(y+ 17)(y - 17)}$

Using the algebraic identity,

$(a + b)(a - b)=a^2-b^2$

$=(z^2 - 1^2)( y^2 - 17^2)$

= $(z^2 - 1)(y^2 - 289)$

∴ The product of z + 1, z - 1, y + 17, y - 17 = $(z^2 - 1)(y^2 - 289)$

Thus, the product of z + 1, z - 1, y + 17, y - 17 is equal to $(z^2 - 1)(y^2 - 289)$.