Question

(z-1) (z+2) = (z+4) (z-2)
how can i do it?​

Answer 1

Answer:

$(z - 1)(z + 2) = (z + 4)(z - 2)$

${z}^{2} + 2z - z - 2 = {z}^{2} - 2z + 4z - 8$

$4z - 5z = - 8 + 2$

$- z = - 6$

$z = 6$