Question

z^2-2z-8=0 find the quadratic equation​

Answer 1

Step-by-step explanation:

Z² - 2z - 8 = 0

z² - 4z + 2z - 8 = 0

z( z - 4) + 2( z - 4)= 0

(z + 2) ( z - 4) = 0

Either,

x + 2=0

x= -2

or,

x -4=0

x= 4

Answer 2

$\large \to \: \: \rm {z}^{2} - 2z - 8 = 0 \\ \\ \large \to \: \: \rm {z}^{2} - 4z + 2z - 8 = 0 \\ \\ \to \: \: \rm z( z- 4) + 2(z - 4) = 0 \\ \to \: \: \rm (z - 4)(z + 2) = 0 \\ \\ \huge \tt \therefore \: \: z = \red 4 \: \: \: or \: \: ( \red{- 2})$