z^2 -2z+i=0.......find the solution of this question
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Step-by-step explanation:
Given ∣z−4∣<∣z−2∣
all complex numbers
lie farther from (2,0)
than from (4,0) as
∣z−4∣<∣z−2∣
So they lie on the side of (z,0) which is
closer to (4,0) than (2,0)
z=x+iy⇒x>3
∴Re(z)>3
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