Math, asked by abhilaxmi1730, 1 month ago

(z^2-3)^2+16=0 find |z|​

Answers

Answered by Rockey12345
0

Answer:

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Step-by-step explanation:

> ( z - 2 )x^2 + ( 5 + x )x + 16 = 0 = > zx^2 - 2x^2 + 5x + x^2 + 16 = 0 = > zx^2- 2x^2 + x^2 + 5x + 16 = 0= > ( z - 1 )x^2 + 5x + 16 = 0 ...

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