Question

z/2 + z/3 + z/4 =13​

Answer 1

Answer:

ANSWER

ANSWERGiven,

ANSWERGiven,z=(2−3i)

ANSWERGiven,z=(2−3i)z

ANSWERGiven,z=(2−3i)z 2

ANSWERGiven,z=(2−3i)z 2 −4z+13

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i)

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=0

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z 2

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z 2 +2z+170

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z 2 +2z+170=4(2−3i)

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z 2 +2z+170=4(2−3i) 3

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z 2 +2z+170=4(2−3i) 3 −3(2−3i)

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z 2 +2z+170=4(2−3i) 3 −3(2−3i) 2

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z 2 +2z+170=4(2−3i) 3 −3(2−3i) 2 +2(2−3i)+170

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z 2 +2z+170=4(2−3i) 3 −3(2−3i) 2 +2(2−3i)+170=4(−46−9i)−3(−5−12i)+2(2−3i)+170

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z 2 +2z+170=4(2−3i) 3 −3(2−3i) 2 +2(2−3i)+170=4(−46−9i)−3(−5−12i)+2(2−3i)+170=−184−36i−3(−5−12i)+2(2−3i)+170

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z 2 +2z+170=4(2−3i) 3 −3(2−3i) 2 +2(2−3i)+170=4(−46−9i)−3(−5−12i)+2(2−3i)+170=−184−36i−3(−5−12i)+2(2−3i)+170=−184−36i+15+36i+4−6i+170

ANSWERGiven,z=(2−3i)z 2 −4z+13=(2−3i) 2 −4(2−3i)+13=−5−12i−8+12i+13=−12i+12i−5−8+13=04z 3 −3z 2 +2z+170=4(2−3i) 3 −3(2−3i) 2 +2(2−3i)+170=4(−46−9i)−3(−5−12i)+2(2−3i)+170=−184−36i−3(−5−12i)+2(2−3i)+170=−184−36i+15+36i+4−6i+170=5−