Question

Z/2+z/3-z/6=8 solvesolvesolvesolve

Answer 1

question:

$\frac{z}{2} +\frac{z}{3} -\frac{z}{6} =8$

Step-by-step explanation:

=>$\frac{z}{2} +\frac{z}{3} -\frac{z}{6} =8$

=>$z(\frac{1}{2} +\frac{1}{3} -\frac{1}{6}) =8$

=>$z(\frac{3}{6} +\frac{2}{6} -\frac{1}{6}) =8$

=>$z(\frac{3+2-1}{6} ) =8$

=>z(4)=48

=>z=12