Question

(z+3)(z-3)-2(z+5)=6​

Answer 1

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Hey Mate!!

(z + 3)(z - 3) - 2(z + 5) = 6

=> $z^{2}$ - $3^{2}$ - 2z + 10 = 6

=> $z^{2}$ - 9 - 2z + 10 = 16

=> $z^{2}$ - 2z + 1 = 16

=> $z^{2}$ - z - z + 1 = 16

=> z(z - 1) - 1(z - 1) = 16

=> (z - 1)(z - 1) = 16

=> $(z - 1)^{2}$ = 16

=> z - 1 = √16

=> z - 1 = 4

=> z = 4 + 1

=> z = 5