Question

(z+3)(z-3)-z(z+4)=6
Solve the following equation​

Answer 1

Step-by-step explanation:

(z+3)(z - 3)-z(z +5)=6

[(z)² - (3)²] - z² - 5z = 6

z² - 9 - z² - 5z = 6

-9 - 5z = 6. {cancelling z² and

-z²}

-5z = 6+9

-5z = 15

z = 15/-5 = -3