Question

(Z+3)(z-3)-z(z+5)=6
Solve this equation

Answer 1

Answer:

(z+3)(z - 3)-z(z +5)=6

[(z)² - (3)²] - z² - 5z = 6

z² - 9 - z² - 5z = 6

-9 - 5z = 6. {cancelling z² and

-z²}

-5z = 6+9

-5z = 15

z = 15/-5 = -3

HOPES IT HELPS!

Answer 2

Step-by-step explanation:

(z+3)(z-3)-z(z+5)=6

z^2-(3)^2-z^2-5z=6

z^2-9-z^2-5z=6

-5z-9=6

-5z=6+9

-5z=15

z=15/-5

z= -3