Z
A rectangular garden is 185 m long and 220 m wide. It has two roads in its centre of
width of 4 m, one parallel to its length and the other parallel to its breadth. Find the co
levelling the roads at 12.50 per square metre.
he n dary inside a square field of 17 m side Find
Answers
The cost of leveling the roads inside the rectangular garden at 12.50 per square metre is Rs. 20,050 .
Step-by-step explanation:
The dimension of the rectangular garden:
Length, l = 185 m
Breadth, b = 220 m
Two roads of width 4 m runs at the centre of the garden and are parallel to the sides of the rectangular garden.
Now,
Area of the path running parallel to the length of the garden = l × w = 185 × 4 = 740 m²
Area of the path running parallel to the breadth of the garden = b × w = 220 × 4 = 880 m²
Area of the common portion between the two cross roads = 4 × 4 = 16 m²
Therefore,
The total area of the roads is given by,
= [Area of the path running parallel to the length] + [Area of the path running parallel to the breadth] – [Area of the common portion]
= 740 + 880 – 16
= 1604 m²
It is also given that the cost of levelling the two roads is Rs. 12.50 per meter square.
Thus,
The cost of levelling the 1604 m² of roads will be,
= Rs. 12.5 × 1604 m²
= Rs. 20050
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Answer:
rupees 2,005
Step-by-step explanation:
I hope this is correct and helpful to you