Z bus covers half the distance at a speed of 4 ms -1 and the remaining half at a speed of 6 ms -1 . what is the average speed of the bus.
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Here,
v₁ = 4 m/s and v₂ = 6 m/s
Since, the distance covered by the bus is same for 1st half and 2nd half.
So, d₁ = d₂
Thus, Average speed = 2 (4 ₓ 6)/(4 + 6) = 2 ₓ 24 / 10 = 4.8 m/s
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Answer:
5m/s
Explanation:
4+6/2=10/2
=5m/s
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