Question

z is a complex no. satisfying | z+1-i|<= 1 . then max value of |z|

Answer 1

Answer:

1

Step-by-step explanation:

z=x+iy

|(x+1)+i(y-1)|≤1

√(x+1)²+(y-1)²≤1

as lhs is positive max value will be at equality

(x+1)²+(y-1)²=1

now its the locus of z which is a circle with radius 1 and centre (-1,1)

Farthest point of the circle from origin = (0,1)

z=i

|z|=1