Question

Z.Jf (a+b):(b+c):(c+a)=6:7:8 and (a+b+c)=14. Then the value of c?​

Answer 1

Answer:

Step-by-step explanation:

(a+b)=6k

(b+c)=7k

(c+a)=8k

Now, we get addition of LHS & RHS

2a+2b+2c=21k

2(a+b+c)=21k

2(14)=21k —————- [given - (a+b+c)=14]

28=21k

k=28/21=4/3 ———————(1)

Since,

a+b+c=14

c=14-(a+b)

we have,

a+b=6k

a+b=6(4/3) ——————-from 1

a+b=8

now,

c=14-(a+b)

c=14–8

c=6