Question

z= log(x+y)
then x by y is equal to​

Answer 1

Answer:

Let

y−z

logx

=

z−x

logy

=

y−z

logz

=k

Now,

xlogx+ylogy+zlogz=k[x(y−z)+y(z−x)+z(y−z)]

⇒logx

x

+logy

y

+logz

z

=0

⇒logx

x

y

y

z

z

=0

⇒x

x

y

y

z

z

=1