Question

Z(p+q) = tan x+tan y​

Answer 1

Answer:

x+y+z=pi

=> tan(x) +tan(y) + tan(z)=tan(x)tan(y)tan(z)

let tan(x)=a

tan(y)=b

tan(z)=c

a+b+c=abc

ab=18

bc=2

(ab)*(bc)=18*2=36

=> ab^2c=36

abc*b=36

(a+b+c)*b=36 (because a+b+c=abc)

ab+b^2+bc=36

18+b^2+2=36

b^2=16

b=4

tan(y)=4

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