Z power x minus 2 is equals to 3 power x + 1 then value of 2 power 1 + X is
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Answer:
Given:
a=\displaystyle\frac{2^{x-1}}{2^{x-2}}a=
2
x−2
2
x−1
b=\displaystyle\frac{2^{-x}}{2^{x+1}}b=
2
x+1
2
−x
\text{and}\;\;a-b=0anda−b=0
\textbf{To find: x}To find: x
\implies\displaystyle\frac{2^{x-1}}{2^{x-2}}-\frac{2^{-x}}{2^{x+1}}=0⟹
2
x−2
2
x−1
−
2
x+1
2
−x
=0
\implies\;2^{x-1-x+2}-2^{-x-x-1}=0⟹2
x−1−x+2
−2
−x−x−1
=0
\implies\;2^{1}-2^{-2x-1}=0⟹2
1
−2
−2x−1
=0
\implies\;2^{1}=2^{-2x-1}⟹2
1
=2
−2x−1
\text{Equating powers on bothsides}Equating powers on bothsides
1=-2x-11=−2x−1
2=-2x2=−2x
\implies\boxed{\bf\;x=-1}⟹
x=−1
\therefore\textbf{The value of x is -1}∴The value of x is -1
\textbf{Find more:}Find more:
If 5^x-1 + 5^x+1=650 then find x
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