Question

z=sin(x^2+y^2),x=t^2+3,y=t^3,usin chain rule find dz/dt

Answer 1

Answer:

Could not understand question

Answer 2

Answer:

z=sin(x^2+y^2) ,x=t^2+3, y=t^3

z=sin(t^4+9+6t^2+t^9)

dz/dt= cos(t^4+9+6t^2+t^9)(4t^3+12t+9t^8)

dz/dt=cos(t^4+9+6t^2+t^9)(9t^8+4t^3+12t) Answer