z-x=20,x+y=160,y+z=180 then what are the values of x,y and z
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z=20+x
x=160-y
y=180-z
z-x=20
substitute the values of z and y
20+x-160-y=20
-140+x-y=20
-160+x-y=0
x-y=160
x+y=160 (i)
x-y=160 (ii)
Using substitution method
x=160-y
Substitute x in eq (ii).
160-y-y=160
160-2y=160
-2y=0
y=0/-2=0
x=160-y
=160-0
=160
z=20+x
=20+160
=180
x=160
y=0
z=180
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