z(x+y); use x=6, y=8 and z=6
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Answer:
How do I solve the equations for x+y=8, x+z=13, z-w=6, and w+y=8?
x+y=8—(1)
x+z=13—(2)
z-w=6—(3)
w+y=8—(4)
Subtracting eqn 1 from eqn 2 we get,
x+z-x-y=13–8
z-y=5—(5)
Adding eqn 3 and eqn 4 we get,
z-w+w+y=6+8
z+y=14—(6)
Adding eqn 5 and eqn 6 we get,
z-y+z+y=5+14
2z=19
z=9.5
Putting this in eqn 6 we get
9.5+y=14
y=4.5
Putting this in eqn 1 we get,
x+4.5=8
x=3.5
Putting y in eqn 4 we get,
w+4.5=8
w=3.5
Answered by
0
Answer:
84
Step-by-step explanation:
If x=6, y=8, and z=6 then we would plug in the values of the given variables into the equation and our new equation would then look like this
6(6+8) which equals 84 because 6+8 equals 14 and 6 times 14 equals 84.
And please let me know if this helps.
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