Math, asked by s9123340, 19 hours ago

z(x+y); use x=6, y=8 and z=6

Answers

Answered by Anonymous
0

Answer:

How do I solve the equations for x+y=8, x+z=13, z-w=6, and w+y=8?

x+y=8—(1)

x+z=13—(2)

z-w=6—(3)

w+y=8—(4)

Subtracting eqn 1 from eqn 2 we get,

x+z-x-y=13–8

z-y=5—(5)

Adding eqn 3 and eqn 4 we get,

z-w+w+y=6+8

z+y=14—(6)

Adding eqn 5 and eqn 6 we get,

z-y+z+y=5+14

2z=19

z=9.5

Putting this in eqn 6 we get

9.5+y=14

y=4.5

Putting this in eqn 1 we get,

x+4.5=8

x=3.5

Putting y in eqn 4 we get,

w+4.5=8

w=3.5

Answered by anthonycharles
0

Answer:

84

Step-by-step explanation:

If x=6, y=8, and z=6 then we would plug in the values of the given variables into the equation and our new equation would then look like this

6(6+8) which equals 84 because 6+8 equals 14 and 6 times 14 equals 84.

And please let me know if this helps.

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