Question

z+y=3 and x-y=1 then the value of x and y are
A) 1,2
B )2,1
C)-1,2
D)2,-1
plz guys with explanations ​

Answer 1

Step-by-step explanation:

I think that it is supposed to be x+y instead of z+y in your question. kindly correct me if I am wrong.

Anyways I hope that my solution helped you.

Answer 2

Appropriate question : Find the values of x and y when $\rm x+y=3$ and $\rm x-y=1$

$~$

$\qquad$ ☁️ $\rm 1,~2$

$\qquad$ ☁️ $\rm 2,~ 1$

$\qquad$ ☁️ $\rm -1,~2$

$\qquad$ ☁️ $\rm 2,~ -1$

$\qquad$______________

Let the two equations be :

$\:$

$\rm \qquad \dashrightarrow \: x + y = 3 \: \: . \: . \: . \: . \: . \: (eq. \: 1)$

$~$

$\rm \qquad \dashrightarrow \: x - y = 1 \: \: . \: . \: . \: . \: . \: (eq. \: 2)$

$\:$

From (eq. 1), let's get the value of x :

$\:$

$\rm \qquad \dashrightarrow \: x = 3 - y \: \:. \: . \: . \: . \: . \: (eq. \: 3)$

$\:$

Substituting the value of x from (eq. 3) in (eq. 2) :

$\rm \qquad \dashrightarrow \: \ \bigg \lgroup3 - y\bigg \rgroup - y = 1$

$\:$

$\rm \qquad \dashrightarrow \: 3 - y - y = 1$

$\:$

$\rm \qquad \dashrightarrow \: 3 - 2y = 1$

$\:$

$\rm \qquad \dashrightarrow \: - 2y = 1 - 3$

$\:$

$\rm \qquad \dashrightarrow \: - 2y = - 2$

$\:$

$\rm \qquad \dashrightarrow \: y = \bigg \lgroup \: \cancel{\dfrac{ - 2}{ - 2} } \: \bigg \rgroup$

$\:$

$\rm \qquad \bold{\dashrightarrow \: y = 1}$

$\:$

Substituting the value of y = 1 in (eq. 1) to find x :

$\:$

$\rm \qquad \dashrightarrow \: x + y = 3$

$\:$

$\rm \qquad \dashrightarrow \: x + 1 = 3$

$\:$

$\rm \qquad \dashrightarrow \: x = 3 - 1$

$\:$

$\bf \qquad \dashrightarrow \: x = 2$

$\qquad$______________

☁️ Therefore, the value of x, y in x + y = 3 and x - y = 1 is 2, 1 [OptionB].